SJR Looper V2 LED Driver by lasersaber | May 16, 2014 | Joule Ringer | 23 comments 23 Comments Stewart on May 16, 2014 at 1:32 pm Hello LS, Can you please provide the following: L1 wire guage & amount of turns L2 wire guage & amount of turns Is there an L3 in this model? Are you using the copper tape? Are the connections from wire to copper tape the same as your first diagram? Thanks Reply lasersaber on May 16, 2014 at 2:32 pm Hi, I do not know the exact turns. Maybe around 4 layers on the primary and 8 on the secondary. I have not yet found the perfect ratio. I do expect to improve performance as I test more coil configurations. I am still using the copper tape. The wire gauge is 18 on the primary and 28 on the secondary. There is a L3 but it is not being used. All the internal coil connections to the copper tape are still the same as in my first diagram. Best regards, LS Reply Stewart on May 16, 2014 at 4:17 pm Great, thank you for your quick response! Reply Alex on May 16, 2014 at 7:17 pm Hi, Short question, the circuit from 3:30 is identical to the big one? Can anyone point out the role of the 3 diodes? Thank you, Alex Reply lukelordoflight on May 16, 2014 at 9:18 pm Hello…. If I am not mistaken, the Diodes are for some backspike energy to the source cap, inductive spikes… correct me, if I am wrong… and 3 diodes, hmmm… maybe just one would be enough, as I tryed it with regular battery and not with cap and some other coilsetup and only one diode… working too…. but perhaps 3 diodes only to reduce stress on each of them..?!? best regards, LLOL Reply kelton on May 17, 2014 at 3:04 pm can i use 2n2222a transistor is the direction of 2 windings are same i think i know how to perfect this circuit plz try every circuit app in itunes or play store it will help u alot Reply lz2sdc on May 18, 2014 at 3:05 pm In my view, the three silicon diodes take positive pulse of high frequency spikes in the base of the transistor, and provide them to the primary winding through which a short time, the capacitor recharge themselves in a small value at the time when the transistor is closed. Something like feedback to the source of energy. You can try a diode between the cathode of the top LED and condenser. Maybe better to work fast switching Schottky diodes as BAS70 – forward voltage 410mV Greetings! lz2sdc Reply Luke on May 19, 2014 at 2:02 pm Hello Alex and Lasersaber! Please correct me, if I am mistaken, but I think the 3 diods take some of the BEMF back to the source? And 3 diods only reduce stress on each of them.. Nice work you are doing lasersaber!!!! Keep it up! We love what you do and that you share it with us and the world! THANKS FOR THAT! Reply Charles Drummond Malcolm Fraser on May 20, 2014 at 1:54 pm Is there any chance you would create a how to video on how to make these please or are you going to be making/patentitng these to sell? We would be interested to buy some tuned for the output of our crystal cells if you would be interested in collaborating to make some products? http://www.sustainablemedia.co/crystalcell Many thanks Charles Reply Thomas on May 20, 2014 at 7:15 pm Hi LS, could you please share a link here to that first diagram you mentioned? thx! Reply John on May 20, 2014 at 10:37 pm What is the value of the ceramic cap? Could the 3 diodes not be replaced with LED’s to get even more light? Could you please do another comparison video with this circuit against DC with the same current draw from an identical ceramic cap? It should kick ass compared with the results of last time. Reply John on May 20, 2014 at 11:18 pm Second question….. This one is maybe important, could you take a second identical ceramic cap to the one above, and replace the 2 LED’s with a single preferably germanium diode and the 2nd charging cap. Once the circuit dies, check the voltage on the charging cap and compare it with the cap that discharged. If the voltage on the charging cap is close to or exceeds the voltage on the cap it ran at, then something extraordinary has occured. Reply Clau on May 21, 2014 at 9:51 am i am wondering if i can use some germanium diodes instead of the 1n4146 … i have a bunch leftover from previous projects and a few transistors that i can use the reason why i want to use germanium diodes is that they have a low dropout voltage so i think that the circuit would be a little bit more efficient… sorry for my bad English Reply Reid on May 23, 2014 at 5:43 am Possabally it uses square waves and producing mhz freqencies because of the harmonics thus needing three diodes. Try a microwave diode and see what happens. Reply reid on May 23, 2014 at 5:47 am http://powermagnetics.co.uk/calculator Use that to optimize your device. Also your Your leave a comment is hard to see because it is in gray instead of black. BTW Keep on the good work.. Reply Reid on May 23, 2014 at 6:01 am Somethings to try.. Small CAP before diode or after Try a bridge rectifier instead of the 3 diodes. if it works try it with small caps. Reply Sandro on May 23, 2014 at 11:10 pm Try a turns ratio of about 1:1.62 golden section. That or 1:3.14 pi should produce some interesting results Reply wildgoose on May 23, 2014 at 11:59 pm Let’s see Q=CV so at 9V the charge on a 3500uF cap is 31.5mC which a couple of 20mA LEDs would drain out in under a second So what do you think is going on for the temaining 12h? Reply Greg Zambo on May 25, 2014 at 4:06 am Hi, Great work! I was just wondering if you have considered replacing the diodes with LEDs as well to make more light. Wouldl that work? Reply Tru168 on May 26, 2014 at 6:09 am Alex: I believe those diodes are actually make use of leakage current to partially bias the transistor. Reply Alexander on June 3, 2014 at 6:26 pm Hello LS, Can you please tell me Inductance each layer of coils? I did 4 layers of the primary coil and 8 layers secondary L1 0.05mh L2 8.21mh As a result, even the LED not starts. Tried different diodes but did not help. Very important to know your coils inductance. Reply Curious Simpleton on June 3, 2014 at 9:13 pm If you daisy chain two or more SJR Loopers, would this accomplish anything? I know you’re focusing on improving a single SJR Looper, but I’m wondering whether daisy chaining SJR Loopers may slow their leak and improve their efficiency. Is it even possible to daisy chain SJR Loopers? Reply d3x0r on June 4, 2014 at 8:19 am Do you have inductance measurements? Reply Submit a Comment Cancel reply Your email address will not be published. Required fields are marked *Comment characters available Name * Email * Website Time limit is exhausted. Please reload CAPTCHA. six + five = Notify me of follow-up comments by email. Notify me of new posts by email.